Question: Linked Lists and sorting in Java The task is to count the frequency of words in a text file, and return the most frequent word

Linked Lists and sorting in Java

The task is to count the frequency of words in a text file, and return the most frequent word with its count. For example,

there are two ways of constructing a software design one way is to make it so simple that there are obviously no deficiencies and the other way is to make it so complicated that there are no obvious deficiencies

Your program should printout the following along with the milliseconds to finish the computing:

The most frequent word is "there" with 3 occurrences.

Question

Question 1 Part A) Analyze the complexities of the algorithms Use the asymptotic analysis to give the complexity of these two algorithms.

Question 1 Part B) Improve Algorithm 1 Algorithm 1 is very slow because of the get(i) method. Improve this algorithm while keeping the LinkedList data structure. A hint is to avoid to use get(i) method while iterating through the list.

The Code:

import java.io.File;

import java.util.Scanner;

import java.util.Map.Entry;

import java.util.AbstractMap;

import java.util.LinkedList;

public class WordCountLinkedList254 {

public static Entry count_ARRAY(String[] tokens) {

int CAPACITY = 10000;

String[] words = new String[CAPACITY];

int[] counts = new int[CAPACITY];

for (int j = 0; j < tokens.length; j++) {

String token = tokens[j];

for (int i = 0; i < CAPACITY; i++) {

if (words[i] == null) {

words[i] = token;

counts[i] = 1;

break;

} else if (words[i].equals(token))

counts[i] = counts[i] + 1;

}

}

int maxCount = 0;

String maxWord = "";

for (int i = 0; i < CAPACITY & words[i] != null; i++) {

if (counts[i] > maxCount) {

maxWord = words[i];

maxCount = counts[i];

}

}

return new AbstractMap.SimpleEntry(maxWord, maxCount);

}

public static Entry count_LINKED_LIST(String[] tokens) {

LinkedList> list = new LinkedList>();

for (int j = 0; j < tokens.length; j++) {

String word = tokens[j];

boolean found = false;

for (int i = 0; i < list.size(); i++) {

Entry e = list.get(i);

if (word.equals(e.getKey())) {

e.setValue(e.getValue() + 1);

list.set(i, e);

found = true;

break;

}

}

if (!found)

list.add(new AbstractMap.SimpleEntry(word, 1));

}

int maxCount = 0;

String maxWord = "";

for (int i = 0; i < list.size(); i++) {

int count = list.get(i).getValue();

if (count > maxCount) {

maxWord = list.get(i).getKey();

maxCount = count;

}

}

return new AbstractMap.SimpleEntry(maxWord, maxCount);

}

static String[] readText(String PATH) throws Exception {

Scanner doc = new Scanner(new File(PATH)).useDelimiter("[^a-zA-Z]+");

int length = 0;

while (doc.hasNext()) {

doc.next();

length++;

}

String[] tokens = new String[length];

Scanner s = new Scanner(new File(PATH)).useDelimiter("[^a-zA-Z]+");

length = 0;

while (s.hasNext()) {

tokens[length] = s.next().toLowerCase();

length++;

}

doc.close();

return tokens;

}

public static void main(String[] args) throws Exception {

String PATH = "/Users/jianguolu/Dropbox/254/code/dblp1k.txt";

String[] tokens = readText(PATH);

long startTime = System.currentTimeMillis();

Entry entry = count_LINKED_LIST(tokens);

long endTime = System.currentTimeMillis();

String time = String.format("%12d", endTime - startTime);

System.out.println("time\t" + time + "\t" + entry.getKey() + ":" + entry.getValue());

tokens = readText(PATH);

startTime = System.currentTimeMillis();

entry = count_ARRAY(tokens);

endTime = System.currentTimeMillis();

time = String.format("%12d", endTime - startTime);

System.out.println("time\t" + time + "\t" + entry.getKey() + ":" + entry.getValue());

}

}

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