Question: Linux ecrypt with private key of encryptation (1 213] over the alphabet = 'A, B, C, ..., Z.!} where the first symbol of the alphabet

 Linux ecrypt with private key of encryptation (1 213] over the

Linux

ecrypt with private key of encryptation (1 213] over the alphabet =" 'A, B, C, ..., Z.!} where the first symbol of the alphabet (a white space) was associated with to the code o. Note: Provide as solution the plaintext of the message as well as the calculations for decrypting the ciphertext

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