Liquid hexane $($A$)$ is placed in a vertical glass tube of inside diameter $0\mathrm{.}95cm.$ The tube is closed at the bottom and open, at the top, to air $($B$)$ flowing at a uniform pressure of $0\mathrm{.}94$atm. The tube assembly is immersed in a constant temperature bath maintained at $19C.$ The hexane evaporates and diffuses through the air column in the tube. The loss volume of liquid hexane is $1\mathrm{.}0c{m}^3$ in $85hr.$ The initial length of air column above the hexane surface is $15\mathrm{.}8cm.$ Please use these information to calculate diffusion coefficient $D_{AB}(c\frac{m^2}{s})$ at $19C.$ The vapor pressure of hexane at $19C$ is $1\mathrm{.}5{10}^{4}Pa$ and the density of liquid hexane $(C_6{H}_{14})$ is $0\mathrm{.}66\frac{g}{c}{m}^3.$

$20\%$