Liquid isobutane is throttled through a valve from an initial state of $360K$ and $4000$kPa to a final pressure of $1860$kPa. Estimate

the temperature change and the entropy change of the isobutane. The specific heat of liquid isobutane at $360K$ is $2\mathrm{.}78J*g^{-1}.C$

$1.($For data, use the characteristic properties of pure species table.$)$

The change in temperature is $-$

K$.$

The change in entropy is

$J*mo{l}^{-1}*K^{-1}.$