Listed below are two solutions for a service issue. In comparing option $1$ to option $2,$ calculate the present worth of costs for option $1$ ove an appropriate number of years so as to properly compare it to option $2.$ Use a $5\%$ interest rate.

$\backslash$table$[[,$Option $1,$Option $2],[$First Cost,$15,000,35,000],[$Maintenance$,1200$ yr$,900$ yr$],[$Salvage$,100,2000],[$Life$,3$years,$6$ years$]]$

Option $1$

a$.18,182$

b$.33,888$

c$.36,356$

d$.41,057$