Live load $50$ dead load $70$ Please help me find witch S beam and Grinder to use Floor System:

${120}^{\text{'}}150\text{'},$ Columns on a ${30}^{\text{'}}$ Grid

Girders span from Column to column in the $150$ foot direction

Beams span between girders

Concrete floor spans across beams

Loading: See table on following page

Elements$/$Materials:

Beams: S$-$Shape

a$.$ Use same beam throughout

b$.$ No deeper than S$12($to limit floor thickness$)$

c$.$ Spacing must be $6^{\text{'}}$ and a factor of ${30}^{\text{'}}($i$.$e$.2\text{'},3\text{'},5\text{'},6\text{'})$

d$.$ Select spacing and S$-$beam that result in the least amount of total steel

Girders: W$-$shape

a$.$ Use same girder throughout

b$.$ Select lightest possible member

c$.$ Approximate load on girder as a distributed load $($rather using multiple point loads from

Girders: W$-$shape

a$.$ Use same girder throughout

b$.$ Select lightest possible member

c$.$ Approximate load on girder as a distributed load $($rather using multiple point loads from the s$-$beams$).$

Material: Steel

a$.ult=50$ksi

b$.$ F$.$S$.=1\mathrm{.}67$

Expectations

a$.$ Clear presentation of your design. I should be able to see very quickly what you final design is $($beams$,$ beam spacing, girders$).$

b$.$ Clear calculations. A third party should be able to review your work in a minimal amount of time, and see the method$/$calculations that led to your

final design.

c$.$ Longer does not necessarily mean better. Clearer always means better.

Grading

a$.$ This problem will be weighted as one whole

Material: Steel

a$.$ ult $=50$ksi

b$.$ F$.$S$.=1\mathrm{.}67$

Expectations

a$.$ Clear presentation of your design. I should be able to see very quickly what you final design is $($beams$,$ beam spacing, girders$).$

b$.$ Clear calculations. A third party should be able to review your work in a minimal amount of time, and see the method$/$calculations that led to your

final design.

c$.$ Longer does not necessarily mean better. Clearer always means better.

Grading

a$.$ This problem will be weighted as one whole HW assignment $($i$.$e$.$ like the

full problem sets that are turned in on Mondays$)$

b$.$ One third of the grade will be based on clarity$/$neatness$.$ The other two

thirds will be based on technical correctness.

Civi $311$ week $10$ Design a floor Systam

Floar system Live load Dead load

$1$

So

$70$

$\frac{(240{30}^2)}{8}=27000$

$\frac{(360{30}^2)}{8}=40500$

$\frac{(600{30}^2)}{8}=67500$

$\frac{(720{30}^2)}{8}=81000$

$\frac{324000}{29940}=10\mathrm{.}82$

$\frac{486000}{29940}=16\mathrm{.}23$

$\frac{8100000}{29940}=27\mathrm{.}05$

$\frac{972000}{29940}=32\mathrm{.}46$