Question: ln(e x2 y-1) = A 1 + 2ln (x) - ln(y) B 2ln (x) - ln(y) C 1 + ln (x) - ln(y) D 1
ln(e x2 y-1) = A 1 + 2ln (x) - ln(y) B 2ln (x) - ln(y) C 1 + ln (x) - ln(y) D 1 + 2ln (x) + ln(y)
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