Question: Look at image below for more to question A constant applied force pp of 11.0N11.0N pushes a box with a mass =8.00kg=8.00kg a distance =15.0m=15.0m

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A constant applied force pp of 11.0N11.0N pushes a box with a mass =8.00kg=8.00kg a distance =15.0m=15.0m across a level floor. The coefficient of kinetic friction between the box and the floor is0.110.

Look at image below for more to questionA constant applied force pp

A constant applied force Fo of 1 1.0 N pushes a box with a mass m = 8.00 kg a distance x = 15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is 0.110. X Fp m Assuming that the box starts from rest, what is the final velocity of of the box at the 15.0 m point? Uf = m/s If there were no friction between the box and the floor, what applied force Fnew would give the box the same final velocity? Fnew = N

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