Question: Looking for Expert tutor in MATH, Who can help me to retype it answer below in WORD FILE and send the link here !! f=

Looking for Expert tutor in MATH, Who can help me to retype it answer below in WORD FILE and send the link here!!

Looking for Expert tutor in MATH, Who can help me to retypeit answer below in WORD FILE and send the link here!! \f=1- 42 = ) 2 = 1 - 42 1 42 1- x ( - 1 ) =) * = ( - 1( 4 -0 ) + 1 = (2-1) = 4p(y-O) 21 =a ly - k ) +b ( 2 - h ) =4ply-1) . vertex = ( hik ) = (1, 0) - )

\f= 1- 42 = ) 2 = 1 - 42 1 42 1 - x ( - 1 ) =) * = ( - 1 ( 4 -0 ) + 1 = (2-1) = 4p(y-O) 21 = a ly - k ) +b ( 2 - h ) = 4ply-1) . vertex = ( hik ) = (1, 0) - ) " HP = - 1 tocay = ( http, k ) = ( 1 -4 10) P = -1 /y = (8, 0 ) 101 2 2 +3 4 2 + 6= 0 the Equation doesnot match the forom any conical section. Not a conical section.\fAxis of symmetry 12= 0 Directsix, 4 = - a = ) y= - 90 n Exp 51 342+ 342 +1821-124-4650 4 . = ) ( 32 2 + 18 x ) + ( 342 - 104 ) = 46 3 ( x 2 + 6x ) + 3 ( 92_ 49 ) = 46 3 ( x 2+ 6 x + ( 3 ) 2 ) + 3 / 42- 49 + ( 2)2 ) = 46+27+12 -) 3 ( x + 3 ) + 3 ( 4 - 2 ) = 85 = ) ( X + 3 ) 2 ( 4 -2 ) 2 ( x - b ) = 1 ( 4 - k ) 2 + Q2 = 1 Center = (h, k ) = (-3, 2) radius - 85 255 3 12 85 x3 2 3x 3 9 1255 3 1 1 6 , 72 42= 0 the above Equation doesnot match the form of any concial section. Not a conical section, Given 1 , 7 2 = 104 the above Equation represents parabola of form - *2 = 404. =) #2= 4 x (40 ) y Here vester = 10, 02 focus ( ofa ) = 10 - 5/ = (0 , 5/2 ) Axis of symmetry , x= 0 , Diretax; y= - a= - 5/, 2, 6 x2 +942 - 24x - 544 + 155=0 ( 6x2- 24x ) + ( 942 544) =-155 6 ( x 2 - 4x ) + 9 ( 4 2 64) =- 15 5 6 ( x2 - 4 x + ( 23 ) + 9 ( 42- 64+ (372 ) =-155+24+81 6 ( X - 2 ) + 9 (4 - 9) ? = - 50 will be always positive negitive. the Equation doesn't match the form of any Conical section. Not a conicsection ,\f\f

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