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Case 1: Teams are evenly matched P(A) = Probability of team A winning = 0.50 P(B) = 0.50 (1) Team A won the first game. For B to win the series , team B must win atleast 3 of the remaining 4 games Probability that Team B wins the series = ⁴C₃(0.50)³(0.50)¹ + ⁴C₄(0.50)⁴(0.50)⁰ = 0.25 + 0.0625 = 0.3125 Case 2: Team B is better than Team A P(A) = 0.45 P(B) = 0.55 Team A won the first game. For team B to win the series, team B must win atleast 3 of the remaining 4 games Probability that Team B wins: ⁴C₃(0.55)³(0.45)¹ + ⁴C₄(0.55)⁴(0.45)⁰ = 0.299475 + 0.091506 = 0.3910

Here is the question:

Playoff series often work by declaring that the rst team to win it games is the champion. Suppose that teams A and B are playing in such a series. In any game in the series, P[team A wins) = p, [0