Looking for help with (2) Rational Expression Problems, Domains and provided vocabulary words to incorporate in explanation of how the problem was formulated.

I've attached a file with the two problems that need to be completed, and here are the requirements for the assignment and vocabularly words to be used...

• Explain in your own words what the meaning of domain is. Also, explain why a denominator cannot be zero.
• Find the domain for each of your two rational expressions.
• Write the domain of each rational expression in set notation (as demonstrated in the example).
• Do both of your rational expressions have excluded values in their domains? If yes, explain why they are to be excluded from the domains. If no, explain why no exclusions are necessary.
• Incorporate the following five math vocabulary words into your discussion. Useboldfont to emphasize the words in your writing. Do not write definitions for the words; use them appropriately in sentences describing your math work.

• Domain
• Excluded value
• Set
• Factor
• Real numbers

\fDomain is the x value in a set, if the set was (x,y); x would be the domain. The denominator of a fraction cannot be zero because a fraction is basically a division problem written a different way and you can't divide something into 0 equal groups, it's not possible, even theoretically. In the expression Y2-25/(-6y) Domain of the above rational expression is \"All Real Numbers\" because the expression accepts all possible value of y except '0'. For 37/(2p-4p2) Or 37/(2p(1-2p)) P cannot have values 0 and So the domain will be all real numbers except 0 and . The Domain for rational expressions is "All Real Numbers " UNLESS it has : 1. a denominator with variables 2. even roots of an expression with variables 3. log or ln expressions with a variable. For the first expression domain in set notation can be written as (-,0) U (0, ) And for the second expression it can be defined as (-,0) U (0, 1/2) U (1/2, ) Since division by 0 is undefined, any values of the variables that result in a denominator of 0 must be excluded. Excluded values must be identified in the original equation, not its factored form. In the second problem 0 and 1/2 are to be excluded. Domains defines what value y or p can take. Domain is the x value in a set, if the set was (x,y); x would be the domain. The denominator of a fraction cannot be zero because a fraction is basically a division problem written a different way and you can't divide something into 0 equal groups, it's not possible, even theoretically. In the expression Y2-25/(-6y) Domain of the above rational expression is \"All Real Numbers\" because the expression accepts all possible value of y except '0'. For 37/(2p-4p2) Or 37/(2p(1-2p)) P cannot have values 0 and So the domain will be all real numbers except 0 and . The Domain for rational expressions is "All Real Numbers " UNLESS it has : 1. a denominator with variables 2. even roots of an expression with variables 3. log or ln expressions with a variable. For the first expression domain in set notation can be written as (-,0) U (0, ) And for the second expression it can be defined as (-,0) U (0, 1/2) U (1/2, ) Since division by 0 is undefined, any values of the variables that result in a denominator of 0 must be excluded. Excluded values must be identified in the original equation, not its factored form. In the second problem 0 and 1/2 are to be excluded. Domains defines what value y or p can take