lso, note that we could find$40(59)$ln$3(59)40(5$x$9)$ln$3(5$x$9)$dx$,$ by replacing the $$u in the expression we found for this integral in terms of $$u$,$ with our expression that we have for $$u in terms of $$x to get$40(59)$ln$3(59)=40(5$x$9)$ln$3(5$x$9)$dx$=$

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Your answer in the line above should be in terms of $$x$,$ ignore the integration constant, $$C

Now, if we were to evaluate this expression at the lower boundary, $=6$x$=6,$ we get$,$ and evaluating it at the upper boundary, $=11$x$=11$ gives$$

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So$,$ we have $11640(59)$ln$3(59)=61140(5$x$9)$ln$3(5$x$9)$dx$=4(59)24(5$x$9)2|116=|611=15291529--44414441==$

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Note $4$ln$2(46)4$ln$2(21)4$ln$2(46)4$ln$2(21)==1675233289$