LT 28 Jay Howell X 3 + 4 3 = 3 p x y , GiND y ( x + e ) + ( y + a ] = 3 p ( x + e ) (y + a ) 1 x z + z x e + e 2 ) ( x + e ) ( u z + z y e + e = ) ( y + a ) = 3 p ( x y + x a + ey + ca ) ( e 3 + 3 e z x + 3 ex 2 + X3 ) + (93 + 302 4 + Bay2 + you = 3 px y + 3 px a + 8 pey + 3pea e 3 + 3 ez x + 3 ex 2 + a3 + 30ky + Bay 22 3 pXat Spey + 3 pea So, we can cancel terus e 3 + 3 ex 2 + 93 + zay ? = 3 pxa+ 3 pley a 3 + Boyz - 3pxa = 3 pey - e3 - Bex2 a = ( 3 py - ( 2 - 3 x 2 ) Where ( 2 = Q2 e' (azzyz - 3 px ) 9 = 3 py - 3x2 e Buzz - 3px DX