$m^{3}f(t)=4-t^{2}tisin$ minutest$=1$ and $t=2.$

Average rate $=\frac{m^3}{m}in$

$b.$ Find the average rate the water leaves $my$ tub between $t=1$ and $t=1\mathrm{.}1.$

Average rate $=\frac{m^3}{m}in$

$c.$ What would you guess $is$ the exact rate water leaves $my$ tub $att=1?$

Average rate $=\frac{m^3}{m}in$

$d.In$ this bit $his$ a very small number. Find the average rate the water leaves $my$ tub between $t=1$ and

$t=1+h.(Simplify$ this $as$ much $as$ possible!$)$

Average rate $=\frac{m^3}{m}in$

$e.$ What $do$ you get $if$ you put $inh=0in$ the answer $to$ part $(d)?$

Answer: $,\frac{m^3}{m}in$