Question: m = m = m = 2 0 % Part ( e ) Several students in your class use different methods to determine the mass

m = m = m=20% Part (e) Several students in your class use different methods to determine the mass of a rock. As their instructor, you know that the mass of the rock is m=25.6084+0.0001 g, as determined using a very precise and accurate method. Which of the following measured masses submitted by the students would you accept as correct? Select all that apply. Remember that different methods of measurements can yield inherently different degrees of precision. Grade Summary m=25.57+0.05 g 25.7+0.1 g m=25.6+0.01 g Deductions 15%26+1 g m=25.607+0.001 g =25.61+0.01 g Potential 85% m=25.60+0.01 g =25.599+0.001 g =25.59+0.01 g

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