m 82 m The elevator at the space needle starts from rest and accelerates relative to...

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m 82 m The elevator at the space needle starts from rest and accelerates relative to its position according to the following equation a(s) = (-0.085s +3) until it reaches its maximum velocity of 9.5. It stays at the maximum velocity until deccelerating at the top. An engineering student takes a ball up the elevator and releases it out the window at 20 m. 8 Animation by Jared Owen used with permission a. How fast (in m )is the elevator (and ball) moving when it is released? b. How high (in meters) will the ball go? 24.6 c. How long will the ball be in the air before it hits the ground? m 82 m The elevator at the space needle starts from rest and accelerates relative to its position according to the following equation a(s) = (-0.085s +3) until it reaches its maximum velocity of 9.5. It stays at the maximum velocity until deccelerating at the top. An engineering student takes a ball up the elevator and releases it out the window at 20 m. 8 Animation by Jared Owen used with permission a. How fast (in m )is the elevator (and ball) moving when it is released? b. How high (in meters) will the ball go? 24.6 c. How long will the ball be in the air before it hits the ground?

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The image displays a physics problem about an elevator and a ball The text states that the elevator at the space needle starts from rest and accelerates according to the equation as 0085s 3 ms until i... View the full answer