m x2- 2x - 3 which the error occurs, and provide the correct work for that step. Sasha's work to express the domain of the function f(x) = in both interval and set builder notation is shown below. Indicate the step at Sasha's Solution 1. Determine restrictions in the denominator. xz- 2x - 3 = 0 (x +1)(x - 3) = 0 x = 1 and 3 2. Determine restrictions in the radicand. -X+3 2 0 x S 3 3. Combine restrictions and express the domain using interval notation. (- 0. - l)U(-1. 3) 4,. Express the domain using set builder notation. {xlxs3,x= -1,xR}