Question: Magnetite (Fe 3 O 4 ) has a spinel structure whose unit cell composition of magnetite (Fe 3 O 4 ) can be represented by

Magnetite (Fe3O4) has a spinel structure whose unit cell composition of magnetite (Fe3O4) can be represented by the formula [Fe2+Fe 3 and 2+O 2- and 4]8. The Magnetite has a cubic unit cell edge length of 0.837nm. Suppose we replace 10% (atomic fraction) of the Fe2+ cations in magnetite with Cu2+ cations while the dimensions of the unit cell are almost identical. Bohr Magnetons of a Fe2+ cation and a Cu2+ cation are 4 and 1, respectively. Bohr Magneton B is equal to 9.2710^-24 Am^2. It is assumed that trivalents Fe3+ ions distribute equally in tetrahedral and octahedral positions, leading to no net contribution of Fe3+ ions to the magnetization of the material. Please estimate

a) The saturation magnetization of the copper ferrite [Fe2+(Cu2+)Fe 3 and 2+O 2- and 4]8 ! (5 points)

b) The saturation flux density of the copper ferrite. Vacuum permeability 0=410^-7 H/m! (3 points)

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Chemical Engineering Questions!