Section Total Score Score a. If A = AES= 0 -(22+). 30 30-2) b. Let matrix...
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Section Total Score Score a. If A = AES= 0 ¹-(22+¹). 30 30-2) b. Let matrix A = 1 2 4. If E= 56 7 I. Filling in the blanks th then adjA= 0 c. Let A= 3, B=(3 1 -2), then BA= Q d. If the vectors v₁ = then det. 0-0 A¹ = 1 2 then EA 3 0 = 5 6 (AB)5: 4 -2, and 7 are linearly dependent, then x=_ e. Let A and B be 4×4 matrices with det(A) = 2, det(B) = -5, and let E be an 4×4 elementary matrix which was formed from I by multiplying its second row by 3, der (-12A) = . det(AT B-¹) = det(EA³) = Section Total Score Score a. If A = AES= 0 ¹-(22+¹). 30 30-2) b. Let matrix A = 1 2 4. If E= 56 7 I. Filling in the blanks th then adjA= 0 c. Let A= 3, B=(3 1 -2), then BA= Q d. If the vectors v₁ = then det. 0-0 A¹ = 1 2 then EA 3 0 = 5 6 (AB)5: 4 -2, and 7 are linearly dependent, then x=_ e. Let A and B be 4×4 matrices with det(A) = 2, det(B) = -5, and let E be an 4×4 elementary matrix which was formed from I by multiplying its second row by 3, der (-12A) = . det(AT B-¹) = det(EA³) =
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Related Book For
Electronic Devices and Circuit Theory
ISBN: 978-0135026496
10th edition
Authors: Robert L. Boylestad, Louis Nashelsky
Posted Date:
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