Match the integral with its answer:

${\displaystyle \underset{1}{\overset{3}{}}}(2x+\frac{1}{x})dx=$

${\displaystyle \underset{\frac{1}{\sqrt[\phantom{2}]{3}}}{\overset{\sqrt[\phantom{2}]{3}}{}}}\frac{8}{1+x^2}dx=$

${\displaystyle \underset{\frac{}{2}}{\overset{0}{}}}cosxdx=$

${\displaystyle \underset{\frac{1}{2}}{\overset{\frac{1}{\sqrt[\phantom{2}]{2}}}{}}}\frac{4}{\sqrt[\phantom{2}]{1-x^2}}dx=$

Choices of answers:

$\backslash$table$[[$A$.,$B$.,$C$.,$D$.,$E$.,$F$.],[,,\frac{}{3},\frac{4}{3},\frac{3}{4},-1]]$

$1$

$[$ Choose $]$

$2$

$3$

$[$ Choose $]$

$4$

$[$ Choose $]$