MATH 131 - Unit 4 1/2021 Class Activity 4.1 (d) Write conclusion in the context of the problem. In conclusion at the.05 level of sign vicance we have sufficient evidence to conclude the mean number of text messages college students And onallypical day is more than of text messages on to support ty and Use Excel or Minitab to find the p-value for your test. # 1 to # 3 still apply. (e) Draw a sketch of the distribution and show where P-value is in the sketch. &= 1,699 *=, 05 =1,499 1 2 3 4 5 6 -Lest Statistic (f) Place the test statistic from (c) on the sketch. (g) Use technology (See below) to find p-value and indicate it on the sketch. P. = 9032 Pvalue s 1-, 9032 =, 0968 (h) Write conclusion in the context of the problem. Remember level of significance is 0.05 D- value is Like 8. We accept it being that it's more than As: 05. We are accepting that the mean a greater than alequal to of text messages. This doe pupport claim by Minitab Excel (XLStat) Select Stat from the menu bar Select a blank column Select Basic Statistics from the subdirectory Fill the column with multiple entries of the value in Select 1t 1-Sample t the null hypothesis, enough to match the data. Click Summarized Data and enter the values from #3 Choose Two sample t and z test from the menu. Choose Paired Samples Type in the hypothesized mean Enter sheet, column letter and rows for the data Enter Alternative hypothesis (including the variable label) under Sample 1 and for Click OK twice the null value under Sample 2. For example, either E1:E41 or 'Sheet1'!E1:41 for Sample 1 and either F1:F41 or 'Sheet1'!F1:41 for Sample 2MATH 131 - Unit 4 Class Activity 1 1/2021 Hypothesis Testing on the Mean 1. Make a claim about the mean number of texts college students send on a typical day. You may use the phrase more than, at least, at most, less than, equal, etc. The average number of texts sent by college students more than 84 Claim 1 284 algebraic opposite is us84 2. Use this statement to develop Ho and Ha. Ho: u 84 claim 3. Collect data from those in class today for 'number of texts sent by college students on a typical day'. Enter this data into Excel or Minitab to find the mean and standard deviation for your sample (your class). Samplesize: 30 Sample moan: 88.4 88,4 S = 1813 Sort Standard . 18.3 deviation 4. Test the hypothesis from #1 using rejection region method. Assume the number of texts sent by college students is a normally distributed population. Assume the population standard deviation has the same value the value listed above for s. K=.05. & = -1.645 (a) Draw a sketch of the distribution. = 1. 645 A Test statistic = 1.3 5 4- 3-2-101 - 34 ers1.645 (b) Place the critical value (cv) on the sketch. Use a level of significance of 0.05 (a = 0.05). (c) Show your calculation for the test statistic test statistic. t = 4 u t= 88.4-84 * / tn = 4:4/ 851 13 18. 3/ 7/30 3, 3