Question: math can be hard 4. -/10 points WANEFMAC7 12.3.012. The position s of a point (in feet) is given as a function of time t

math can be hard

math can be hard 4. -/10 points WANEFMAC7 12.3.012. The position sof a point (in feet) is given as a function of timet (in seconds). HINT [See Example 1.] s = -11 + t- 18t2; t = 3 (a) Find the point's acceleration as a

4. -/10 points WANEFMAC7 12.3.012. The position s of a point (in feet) is given as a function of time t (in seconds). HINT [See Example 1.] s = -11 + t - 18t2; t = 3 (a) Find the point's acceleration as a function of t. s"(t) = ft/sec2 (b) Find the point's acceleration at the specified time. s"(3) = ft/sec2 Need Help? Read It Talk to a Tutor 5 -/10 points WANEFMAC7 12.3.015. The position s of a point (in feet) is given as a function of time t (in seconds). HINT [See Example 1.] s = vt + 5t2; t = 9 (a) Find the point's acceleration as a function of t. s"(t) = ft/sec2 (b) Find the point's acceleration at the specified time. s"(9) = ft/sec2 Need Help? Read It Watch It Talk to a Tutor6. 0/10 points V Previous Answers V WANEFMAC7 12.3.018. The graph of a function is given. Find the approximate coordinates of all points of inflection of the function (if any). (If there are no inflection points enter DNE.) ( x, y ) = 8, - 8 X 8 X Need Help? Read It Talk to a Tutor7. 0/10 points V Previous Answers V WANEFMAC7 12.3.020. The graph of a function is given. Find the approximate coordinates of all points of inflection of the function (if any). (If there are no inflection points, enter DNE.) ( x, y ) = DNE x ) 3 X Need Help? Read It Watch It Talk to a Tutora(t) = 0 increasing 0 decreasing V The position of a particle moving in a straight line is given by s = t3 ft/s2 Is its velocity increasing or decreasing when t = 8? Need Hem 1'2 feet after 1' seconds. Find an expression for its acceleration a after a time t

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