. Mathematica understands the usual notation for higher derivatives: y'[x], y"[x], and y"[x] A single equals sign is used to assign names, For the equation itself, a double equals sign, = =, is used. We haved defined the function f[x_] = Ex Cos[x]. To plug it in to the equation we relace y with f using the repacement (slash dot) command, like this: eqn /. y -> f When we input this into Mathematica, the output is True which means the equation is true, so f is in fact a solution. ? Question In Mathematica, define the above equation and the function f(x) = esin(x) and use it to check if f is a solution. What output does Mathematica give you? Next, define the new function f2(x) = 3x in Mathematica (we can define this as a new function named f2, as in f2[x_]=3x) and plug f2 into the equation. What output does Mathematica give you? Question Help: Message instructor D Post to forum Submit Question Next Page Oequation with initial condition y(0) = -1. ? Question In Mathematica, plot the function f(x) = 4es - 2e " and adjust the plot so you can see where the graph crosses the y-axis. y(0) =] Question Help: Message instructor O Post to forum Submit Question Next Page Oof a differential equation with initial condition y(0) = -1. ? Question In Mathematica, plot the function f(x) = 4e34 - 2e- and adjust the plot so you can see where the graph crosses the y-axis. y(0 ) = Question Help: Message instructor O Post to forum Submit Question Next Page O