Matlab

Assume that at each row of a 2D character array there is a string which can have duplicate characters. Using Octave, write a function called "is existing" that will accept two inputs: An array (say X) with above-given properties, and another 2D character array (say Y) whose number of columns is equal to the number of columns of X. The number of rows of these two arrays can be different. The output will be a column vector whose number of rows is equal to the number of rows of Y. For any row of Y, if there exists a row of X that is composed of a permutation of the string given in this row of Y, the corresponding element of the output vector will be logical 1. Otherwise, it will be logical 0. (You may NOT use any built-in functions except size. length, rem and mod) Example: 13336 'VZEL8A3V '99 '919EY9EN' 'C3C3C3C3' Y =631A3B3C' 99) X = If Z-is_existing(X,Y), Z = 1