Question: Max 2 5 0 0 E + 2 1 0 0 L s . t . 6 E + 4 L < = 2 4

Max 2500E +2100L
s.t.
6E+4L <=2400
L <=250
3E +4L <=1500
E,L >=0
What is the optimal solution value for E (number of units of the EZ-Rider)? What is the profit?

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