Question: max z = 4 0 x 1 + 5 0 x 2 s . t . x 1 + 2 x 2 < = 4

max z =40x1+50x2
s.t. x1+2x2<=40 hr. of labor
4x1+3x2<=120 lb. of clay
x1, x2>=0(x1: number of bowls, x2: number of mugs)
This is a standard linear programming model; as such, it has a single objective function for profit. However, let us suppose that instead of having one objective, the pottery company has several objectives, listed here in order of importance: 1. To avoid layoffs, the company does not want to use fewer than 40 hours of labor per day. 2. The company would like to achieve a satisfactory profit level of $1,600 per day. 3. Because the clay must be stored in a special place so that it does not dry out, the company prefers not to keep more than 120 pounds on hand each day. 4. Because high overhead costs result when the plant is kept open past normal hours, the company would like to minimize the amount of overtime. Solve the problem as a GP.

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