A design team is in the process of designing a gyro-stabilizer for a boat against rolling....

 

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A design team is in the process of designing a gyro-stabilizer for a boat against rolling. Motor 4 in Figure I takes the signal from the water wave and turns the large precession gear B up to a maximum of ± 60° (measured with the vertical x-axis) Gear B then rotates the Gimbal to actively generate T and cancel the torque caused by the wave. The rotor turns inside the housing at a speed of 3000 rev/min (about x-axis) and has already been decided by the design team. Dimensions and mass properties of the rotor are given in Figures 2 and 3 respectively Assume that the motor rotates the gimbal 30 deg/s when the boat rolls at a rate of 10 deg/s. Help the design team by performing the following tasks 1. Decide the frame of the gyro system to connect all parts to it. Show all dimensions Take rotor dimensions as a reference 2 Calculate Tro, Tree, and bearing forces at C, D, E and F. 3. Choose appropriate motor 4. Select suitable pinion and Gear B 5. Select suitable bearings at C. D. E and F. 6. Decide the weld pattern and size at G and H. Assume suitable safety factor and make justified assumptions wherever required Grading: Progress/log book (10 points), Report (10 points) Port (left) Motor A B Vertical AX Gimbal Figure 1: A gyro stabilizer Rotor T 2010 ET Forward Starboard (right) 380 mm 550 mm 500 mm- Figure 2: The rotor dimensions. 1, 2 and 3 represents the principal axes. MATERIAL BRASS VOLUME= 2.3276647e-02 M^3 SURFACE AREA - 0.9302 M^2 DENSITY - 8460.0000 KILOGRAM/M^3 MASS= 196.9204 KILOGRAM CENTER OF GRAVITY with respect to ROTOR coordinate frame (Meter): X Y Z 0.0000000e+00 0.0000000e+00 0.0000000e+00 INERTIA with respect to ROTOR coordinate frame: (KILOGRAM * M^2) INERTIA TENSOR: Ixx Ixy Ixz 6.9726839e+00 0.0000000e+00 0.0000000e+00 Iyx Iyy Iyz 0.0000000+00 4.3995836e+00 0.0000000e+00 Izx Izy Izz 0.00000000+00 0.0000000e+00 4.39958530c+00 INERTIA at CENTER OF GRAVITY with respect to ROTOR coordinate frame: (KILOGRAM M^2) INERTIA TENSOR: Ixx Ixy Ixz 6.9726839e+00 0.0000000e+00 0.0000000e+00 Iyx Iyy Iyz 0.0000000e+00 4.3995836e+00 0.0000000e+00 Izx Izy Izz 0.0000000e+00 0.0000000e+00 4.3995853e+00 PRINCIPAL MOMENTS OF INERTIA: (KILOGRAM M^2) 11 12 13 4.3995818e+00 4.3995871e+00 6.9726839e+00 RADII OF GYRATION with respect to PRINCIPAL AXES (Meter): R1 R2 R3 0.14947216 0.14947225 0.18817182 Figure 3: Rotor mass properties A design team is in the process of designing a gyro-stabilizer for a boat against rolling. Motor 4 in Figure I takes the signal from the water wave and turns the large precession gear B up to a maximum of ± 60° (measured with the vertical x-axis) Gear B then rotates the Gimbal to actively generate T and cancel the torque caused by the wave. The rotor turns inside the housing at a speed of 3000 rev/min (about x-axis) and has already been decided by the design team. Dimensions and mass properties of the rotor are given in Figures 2 and 3 respectively Assume that the motor rotates the gimbal 30 deg/s when the boat rolls at a rate of 10 deg/s. Help the design team by performing the following tasks 1. Decide the frame of the gyro system to connect all parts to it. Show all dimensions Take rotor dimensions as a reference 2 Calculate Tro, Tree, and bearing forces at C, D, E and F. 3. Choose appropriate motor 4. Select suitable pinion and Gear B 5. Select suitable bearings at C. D. E and F. 6. Decide the weld pattern and size at G and H. Assume suitable safety factor and make justified assumptions wherever required Grading: Progress/log book (10 points), Report (10 points) Port (left) Motor A B Vertical AX Gimbal Figure 1: A gyro stabilizer Rotor T 2010 ET Forward Starboard (right) 380 mm 550 mm 500 mm- Figure 2: The rotor dimensions. 1, 2 and 3 represents the principal axes. MATERIAL BRASS VOLUME= 2.3276647e-02 M^3 SURFACE AREA - 0.9302 M^2 DENSITY - 8460.0000 KILOGRAM/M^3 MASS= 196.9204 KILOGRAM CENTER OF GRAVITY with respect to ROTOR coordinate frame (Meter): X Y Z 0.0000000e+00 0.0000000e+00 0.0000000e+00 INERTIA with respect to ROTOR coordinate frame: (KILOGRAM * M^2) INERTIA TENSOR: Ixx Ixy Ixz 6.9726839e+00 0.0000000e+00 0.0000000e+00 Iyx Iyy Iyz 0.0000000+00 4.3995836e+00 0.0000000e+00 Izx Izy Izz 0.00000000+00 0.0000000e+00 4.39958530c+00 INERTIA at CENTER OF GRAVITY with respect to ROTOR coordinate frame: (KILOGRAM M^2) INERTIA TENSOR: Ixx Ixy Ixz 6.9726839e+00 0.0000000e+00 0.0000000e+00 Iyx Iyy Iyz 0.0000000e+00 4.3995836e+00 0.0000000e+00 Izx Izy Izz 0.0000000e+00 0.0000000e+00 4.3995853e+00 PRINCIPAL MOMENTS OF INERTIA: (KILOGRAM M^2) 11 12 13 4.3995818e+00 4.3995871e+00 6.9726839e+00 RADII OF GYRATION with respect to PRINCIPAL AXES (Meter): R1 R2 R3 0.14947216 0.14947225 0.18817182 Figure 3: Rotor mass properties

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1 Frame Design The frame of the gyro system should be designed to connect and support all the compon... View the full answer