mean = 3.67 standard dev = 2.16 3.67 - 1.5 x 2.16 = 0.43 3.67 + 1.5 x 2.16 = 6.91 Step 3 - You are asked by your research supervisor to remove all scores that are outliers. According to your supervisor, outliers are values less than or greater than 1.5 standard deviations from the mean. State the cut-offs you would use to two decimal places: Lower cut-off= Upper cut-off=