Prove that if (sum_{n = 0}^{infty} a_{n}x^{n}) converges for x = x_0 and diverges for x = x_1, then: a. (sum_{n = 0}^{infty} a_{n}x^{n}) converges absolutely for |x| < (less than) |x_0| and b. (sum_{n = 0}^{infty}) diverges for |x| > (greater than) |x_1| 

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a If the sum converges for x x0 then the terms in the sum must approach 0 as n approaches infinity T... View the full answer