Question: Memory Performance: mont Processor P 1 : 3 6 % of all instructions are memory access instructions. Level 1 Cache Access = 0 . 7

Memory Performance: mont Processor P1: 36% of all instructions are memory access instructions. Level 1 Cache Access=0.74 ns (= cycle time) Main Memory Access =75 ns 11% of all memory access is a "miss". 9. The clock rate of the processor GHz.10 The Average Memory Access Time for the given data =11. The Average number of cycles for a memory access= cycles 12. Assuming that the base CPI =1.0 cycles, and using the answer from #11, cycles the average CPI for P1 for the information described ns Now, consider processor P2, with the addition of a Level 2 Cache, with an access time of 4.6 ns and a "miss" rate of 91%.13. The Average Memory Access Time for the given data =.. ns 14. The Average number of cycles for a memory access = cycles 15. Assuming that the base CPI =1.0 cycles, and using the answer from #14, the average CPI for the program described = cycles 16. Assuming that the base CPI =1.0 cycles, and using the answer from # 15, alle the average time for the program described ns. awiyad Finally, consider processor P3, but instead of adding Level 2 cache, the size of the Level 1 cache is increased giving a new access time of 88 ns and a "miss" rate of 8%. ber slavo joob 17. The Average Memory Access Time for the given data= ns Hyl 18. The Average number of cycles for a memory access = cycles 19. Assuming that the base CPI =1.0 cycles, and using the answer from #14, the average CPI for the program described = cycles 20. Assuming that the base CPI =1.0 cycles, and using the answer from # 15,robn't goinh the average time for the program described ns.21. Which processor performs better for the program described? (P1, P2 or P3) nicM 22. Why??

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