Question: method BadNbr ( a: array ) returns ( bn: int ) { / / Step 1 : Check the edge case for an array with

method BadNbr(a: array) returns (bn: int)
{
// Step 1: Check the edge case for an array with fewer than 2 elements
if a.Length 2{
return -1;
}
// Step 2: Initialize bn to -1 to indicate no bad neighbor found by default
bn :=-1;
var n := a.Length;
// Step 3: Check the wrap-around pair (last element with the first element)
if a[n-1]+ a[0]0{
return 0; // The first element is a bad neighbor
}
// Step 4: Iterate over each consecutive pair in the array
var i :=0;
while i n -1{
// Check if the sum of current and next element is negative
if a[i]+ a[i +1]0{
return i +1; // Return the index of the first bad neighbor found
}
i := i +1;
}
// Step 5: If no bad neighbor is found, return -1
return -1;
}
method TestBadNbr(){
// Test case 1: Empty array
var arr1 := new int[0];
var res1 := BadNbr(arr1);
assert res1==-1;
// Test case 2: Array with one element
var arr2 := new int[1];
arr2[0] :=5;
var res2 := BadNbr(arr2);
assert res2==-1;
// Test case 3: Array with two elements where sum is negative
var arr3 := new int[2];
arr3[0] :=1;
arr3[1] :=-2;
var res3 := BadNbr(arr3);
assert res3==1;
// Test case 4: Array with three elements and a bad neighbor pair
var arr4 := new int[3];
arr4[0] :=3;
arr4[1] :=-4;
arr4[2] :=1;
var res4 := BadNbr(arr4);
assert res4==1;
// Test case 5: Array with four elements and a wrap-around bad neighbor pair
var arr5 := new int[4];
arr5[0] :=2;
arr5[1] :=-1;
arr5[2] :=3;
arr5[3] :=-4;
var res5 := BadNbr(arr5);
assert res5==3;
// Additional test case: No bad neighbor
var arr6 := new int[3];
arr6[0] :=3;
arr6[1] :=2;
arr6[2] :=1;
var res6 := BadNbr(arr6);
assert res6==-1;
// Additional test case: Only wrap-around is a bad neighbor
var arr7 := new int[4];
arr7[0] :=-1;
arr7[1] :=2;
arr7[2] :=3;
arr7[3] :=-4;
var res7 := BadNbr(arr7);
assert res7==0;
}
why will assertion not hold? how do I fix this?
method BadNbr ( a: array ) returns ( bn: int ) {

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