Question: Methyl iodide can be produced by reacting hydro - iodic acid with an excess methanol via the reaction: H I + C H 3 O

Methyl iodide can be produced by reacting hydro-iodic acid with an excess methanol via the reaction:
HI+CH3OHCH3I+H2O
A typical process for the production of methyl iodide is indicated in the following figure. The feed to the reactor contains 2.1 moles CH3OH per 1molHI. The single pass conversion of HI is 50% conversion and 90% of the H2O entering the first separator leaves in stream 5. All compositions are in molar basis.
How many moles of CH3I are produced per mole of fresh HI feed?
Methyl iodide can be produced by reacting hydro-iodic acid with an

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