mg a = m+ Use the following values in the numerical analysis that follows: m = 50 9, large = 2.4 cm, small = 1.45 cm, Rdisc = 4.75 cm, Mdisc = 120 9, and g = 9.8 m/s'. Assume that the disc is a solid, circular disc. In calibrating your video analysis, use the fact that the rotary motion sensor has a height of 4.04 cm. Make sure to include only the side of the sensor and not the bottom while setting the scale. Fly wheel Large pulle Small pulley 4.04cm What is the numerical value of a for the large pulley? alarge = 0.706 x m/s2 What is the numerical value of a for the small pulley? asmall = m/s2 Based on your results, which pulley, large or small, resulted in a larger linear acceleration a of the falling mass? What does this result tell you about how the kinetic energy of the falling mass depends on the pulley's size? What does it tell you about the kinetic energy of the fly wheel? Does it match your results from the first part of the problem? Explain