Midterm $1$: Over Sections $2\mathrm{.}1-2\mathrm{.}5$

Score: $7\mathrm{.}71/50$ Answered: $6/14$

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Find the derivative of each function.

Do not change negative exponents to positive and do not change rational exponents to radicals

$f(x)=\frac{3\sqrt[3]{x^2}}{x^{3}6}$

$f^{\text{'}}(x)=$

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$2.f(x)=\frac{15x^{3}15}{3\sqrt[3]{x^2}}$

$f^{\text{'}}(x)=$

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