Question: minimum expected count is 8.00. a) State a reason of choosing the Chi-Square Test of Independence for this study. (1 mark) b) Calculate the values




minimum expected count is 8.00. a) State a reason of choosing the Chi-Square Test of Independence for this study. (1 mark) b) Calculate the values of A and B. (5 marks) c) At the 5% significance level, test whether education level is associated to his or her place of residence. (4 marks)QUESTION 7 A researcher wants to investigate whether the education level is related to his or her place of residence. Hundred's people were selected randomly. The results are given as follow. Area * Education Level Crosstabulation Education Level Bachelor's SPM Diploma Degree Total Area Urban Count 22 10 18 50 Expected Count 25.0 8.0 17.0 50.0 Rural Count 28 6 16 50 Expected Count 25.0 8.0 A 50.0 Total Count 50 16 34 100 Expected Count 50.0 16.0 34.0 100.0 Chi-Square Tests Value Pearson Chi-Square B' Likelihood Ratio 1.850 2 Linear-by-Linear Association 778 N of Valid Cases 100 a, 0 cells (0.0%) have expected count less than 5. The minimum expected count is 8 00 a) State a reason of choosing the Chi-Square Test of Independence for this study. (1 mark)
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