MIPS Programming

On high level programming, I understand that in order for this to work, the required loop would involve taking original[i][j] > translated[j][i], but I'm having trouble translating that into MIPS. I'd also imagine that you would need to take into account 4 bytes between each element when saving the original data to the translated data.

Write an assembly program that swaps the columns and the rows of a 6x6 matrix as it is depicted in the following example. The assembly code snippet provides the initial matrix and the position of the result 1 23 456 7 8 9 10 1 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 1 7 13 19 25 31 2 8 14 20 26 32 3 9 15 2 27 33 4 10 16 22 28 34 5 11 17 23 29 35 6 12 18 24 30 36 .data 0x10000800 OrinRow 0 word 1,2,3,4,5,6 OrinRow 1: .word 7,8,9,10,11,12 OrinRow 2: .word 13,14,15,16,17,18 OrinRow 3: .word 19,20,21,22,23,24 OrinRow 4: word 25,26,27,28,29,30 OrinRow 5:.word 31,32,33,34,35,36 .data 0x10000900 TransRow 0 .word 0,0,0,0,0,0 TransRow 1: .word 0,0,0,0,0,0 TransRow 2:.word 0,0,0,0,0,0 TransRow 3:.word 0,0,0,0,0,0 TransRow 4 .word 0,0,0,0,0,0 TransRow 5 .word 0,0,0,0,0,0 . text 0x00400000 main: #Your code starts from here