Modify the program $12-10$ from pages $839$ as follows:

$1.$ Add a third C$-$string as name$3[$NAME$\_$LENGHT$].$

$2.$ Add a pair of cout$/$cin$.$getline$()$ for the third string similar to the ones for first and second strings.

$3.$ Add the appropriate case to the $"$if$/$else if$"$ structure such that the three strings will be displayed in alphabetical order.

Hint: There are $6$ possible cases $(3!,3$ factorial $=3*2*1=6)$ for all complete permutations. The easiest way to test is to input the three strings as single letters like: $"$a$","$b$",$ and $"$c$".$ Your $"$if$/$else if$"$ condition check should cover all $6$ cases for the possible input order like: abc, acb, bac, bca, cab, cba. Regardless of the input order the output should be always abc.

First $"$if$"$ condition check is like:

if $($ strcmp$($name$1,$name$2)<mtext\; id="EditorElement\_4614400"></mtext><mn\; id="EditorElement\_4614401">0</mn>$ && strcmp$($name$2,$name$3)<mtext\; id="EditorElement\_4614428"></mtext><mn\; id="EditorElement\_4614429">0</mn><mtext\; id="EditorElement\_4614430"></mtext><mi\; id="EditorElement\_4614431">)</mi>$

cout $$ name name name$3$ endl;

else if $($ strcmp$(...$

You have to complete the rest of the $5$ "else if$"$ condition. The last "else" can be used to display the message that all three strings are the same.