Modify the template program, $$lookout$.$c$$ on p$.56-57$ with the following additional capabilities

Repeat the following steps $5$ times $($this means, after $5$ seconds of running, your program should terminate without printing anything if there is no change detected.$)$

Wait $1$ seconds using $$sleep$(1)$ call

Call $$stat$$ system call to extract the file attributes against given files in command line arguments $($the lookout.c program in p$.56$ may accept up to $10$ files$).$ Your program should be able to accept up to $10$ files for monitoring.

You program should check any changes in any of the following attributes:

st$\_$mode

st$\_$nlink

st$\_$size

st$\_$atime

st$\_$mtime

When your program detects any changes, your program should immediately print out number codes given below and EXIT!

Change of st$\_$mode $$ print $1$

Change of st$\_$nlink $$ print $2$

Change of st$\_$size $$ print $3$

Change of st$\_$atime $$ print $4$

Change of st$\_$mtime $$ print $5$

Once printing is done, your program should terminate. Make sure your condition checking and printing should be done in the above order! Make sure you print number codes in one line $($without any newline character$)!$

Example output when you change the file contents $($e$.$g$,$ using vi$)$: $345$

If your program prints more than one number code, then place spaces in between.

Important: if your program doesn$$t print the corresponding number codes or if it prints more information than number codes, then your program will fail the tests, and you will get zero point for the tests. If there is no change detected during your program's execution, your program should exit without printing anything.

Testing of your program can be done by opening two terminals, and run $$lookout$$ in one terminal and, in another terminal, make some changes to the file contents, file permission modes, number of links, by using a variety of shell commands such as $$vi$,$chmod$,$link$,$unlink$,$ etc.

In the terminal where $$lookout$.$c$$ is running, the program should print the assigned code into display and exit.

Here is the lookout.c template program:

$//$ lookout $--$ print message when file changes

#include

#include

#include

#define MFILE $10$

void cmp$($const char $*,$ time$\_$t$)$;

struct stat sb;

int main$($int argc, char $**$argv$)$

$\{$

int j;

time$\_$t last$\_$time$[$MFILE$+1]$;

if $($argc $<2)\{$

fprintf$($stderr$,$ "usage: lookout filename $...$

$")$;

exit$(1)$;

$\}$

$//$int stat$($const char $*$path$,$ struct stat $*$buf$)$;

if $(--$argc $>$ MFILE $)\{$

fprintf$($stderr$,$ "lookout: too many filenames

$")$;

exit$(1)$;

$\}$

$//$Initialization

for$($j $=1,$ j $<=$ argc; j$++$;$)$

if$($stat$($argv$($j$),$ &sb$)==-1)$

$\{$

fprintf$($stderr$,$ "lookout: couldn't stat $\%$s

$",$ argv$($j$))$;

exit$(1)$;

$\}$

last$\_$time$($j$)=$ sb$.$st$\_$mtime;

$//$loop until file changes

for$($;;$)$

$\{$

for$($j $=1$; j $<=$ argc; j$++)$

cmp$($argv$($j$),$ last$\_$time$($j$))$;

$/*$rest for $60$ SECONDS "sleep" is a standard UNIX library routine $*/$

sleep$(60)$;

$\}$

$\}$

void cmp$($const char $*$name$,$ time$\_$t last$)$

$\{$

$/*$as long as statics about the file can be read check the modification time $*/$

if$($stat$($name$,$ &sb$)==-1||$ sb$.$st$\_$mtime $!=$ last$)$

$\{$

fprintf$($stderr$,$ "lookout: $\%$s changed

$",$ name$)$;

exit$(0)$;

$\}$

$\}$

Please show test runs so I can compare if something goes wrong when I test it myself.