Module Two Discussion Question: Solve the problem below. For your initial post in Brightspace, copy the description of your cylinder in the box below and then enter your solution to all three parts (parts a, b, and c) of the problem. To copy the description of your cylinder, highlighting and using "copy" from here in Mobius and then using "paste" into Brightspace should work. Hint: This is similar to Question 63 in Section 5.7 of our textbook. We covered this section in \"l- 4 Reading and Participation Activities: Inverses and Radical Functions" in Module One. You can check some of your answers to parts b and c to make sure that you are on the right track. The height of the cylinder is 5 inches. We'll be analyzing the surface area of a round cylinder - in other words the amount of material needed to Quit & Save Previous Unit item Next Unit Item A cylinder (round can) has a circular base and a circular top with vertical sides in between. Let 1' be the radius of the top of the can and let I: be the height. The surface area of the cylinder, A, is n.....l.- .. -....n A = 21772 + 21r'rh (it's two circles for the top and bottom plus a rolled up rectangle for the side). r_- radius Areas = n 12: h = he'ight Area =-h(21u') Circumference 2m Part a: Assume that the height ofyour cylinder is 8 inches. Consider A as a function of 1', so we can write that as A (r) = 2 m2 + 16 rrr. What is the domain of 110-)? In other words, for which values of r is A (1') dened? Part I): Continue to assume that the height of your cylinder is 8 inches. Write the radius r- as a function of A. This is the inverse function to A (1'), i.e to turn A as a function of? into. 1' as a function ofA. ab 5min) on c- M 0 tools D My courses a My books My folder Career Life tools v My courses v My books My folder Career Life ON per post (D r question is answered 6) Id Check your work Our Honor Code :tion