$\backslash$mu $\_($water $)=0\mathrm{.}001($ny$)/(($m$)-$s$)$

$\backslash$rho $\_($water $)=998(($kg$))/($m$^(3))$

Pipe $\_()$

$(\backslash$epsi $)/($D$)=0\mathrm{.}008$

For laminar flow: $\backslash$alpha $=2$

For turbulent flow: $\backslash$alpha $=1\mathrm{.}058$D$=200$mm$,$L$\_(1)=9$m$,$L$\_(2)=$

$3\mathrm{.}4$ m $,$ and L$\_(3)=1\mathrm{.}5$m $0\mathrm{.}210($m$^(3))/($s$).$ It enters the system

inside the pipe at A and exits to the atmosphere at C$.$ The gage pressure at A has

dipped to only $3600$ Pa $,$ meaning a pump had to be installed as shown to help push

the flow through the system and out at C$.$

The gate valve at B is fully open, and the elbows are all regular $90\backslash$deg elbows. All

fittings are flanged, there are no entrance or exit effects for the system, and the

diameter can be treated as $8$ inches for the purposes of reading the minor losses

chart $($for your other calculations, use $200$ mm $).$

Based on this information and that provided in the diagram, determine the power the

pump puts into the system in kW$.$ Use the friction factor equation given since coding

a value into iLearn prohibited the use of approximate values from reading the Moody

Chart $($you will still need to read the Moody Chart on exams$).$ Question $2(10$ points$)$