Multi Channel System: Ls = Lg +1/u. Ws = +Ls/2. W, = +Lq/. Pw = Lq (Su/1 1) Customers arrive at a common queue at the coffee station with two identical coffee machines in a busy mall at the rate of 48 per hour, following a Poisson distribution. Each customer mixes his or her specialty coffee taking 2 minutes on average following an exponential process. What is the expected number of customers in the system at this coffee station? SM 2 2 au 0.6 0.8 VO 1.2 W.4 11.6 2 2 2 2 0.059 0.152 0.333 0.675 11.345 2.844 4 444 CM 0.952 G 2.844 W 1.6 = Single channel, constanu service time: La = 12/2u(p-1). W, = L2/1). Ls = Lq + 1/pu. Ws = 15/1 Customers arrive at a single self-serve coffee machine in a busy mall at the rate of 20 per hour, following Poisson distribution. Each customer takes exactly 90 seconds to get his or her coffee. What is the expected number of customers in queue at this coffee machine? 3.0 0.25 O 1.5 O 0.75 Moving to another question will save this response. Question 16 of 32