My Incorrect Ansurer

$M_E=0$;

$-A_y*20m=1$kNsen$30*15m+1kN*cos30*Y$

$tan60=\frac{y}{5}5*tan60=y=3m$

$A_y=505W$

Answer:

The a pplied load is normal to the sepppont at $E$

and collinear with member de$.$

The full load is resisted by the Seppout at E$.$

so there is no reaction at $A.$

Questions:

"The a pplied load is normal to the suppont at E

and collinear with member DE$."$

so what?

why is that important?

How contributes to Ax and Ay be zero?

what static concepts or laws sustaint the

argumont?

"The full load is resisted by the seppout at $E_1.$

why?