My library $>$ CSC $1230$: Problem Solving and Programming home $>2\mathrm{.}4$: Floating$-$point $($double$)$

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What is output by cout $$ fixed $$ setprecision$(3)<mtext\; id="EditorElement\_150798"></mtext><mn\; id="EditorElement\_150779">9</mn><mn\; id="EditorElement\_150780">.</mn><mn\; id="EditorElement\_150781">1</mn><mn\; id="EditorElement\_150782">3</mn><mn\; id="EditorElement\_150783">5</mn><mn\; id="EditorElement\_150784">7</mn>$; $?$

$9\mathrm{.}136$

$9\mathrm{.}135$

Correct

cout $$ fixed $$ setprecision$(3)9\mathrm{.}1357$; outputs $9\mathrm{.}136$ because the third digit after the decimal point is rounded.

$9\mathrm{.}14$

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CHALLENGE

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$2\mathrm{.}4\mathrm{.}1$: Sphere volume.

Given sphereRadius, compute the volume of a sphere and assign sphereVolume with the result. Use $(4\mathrm{.}0/3\mathrm{.}0)$ to perform floatingpoint division, instead of $(4/3)$ which performs integer division.

Volume of sphere $=(\frac{4\mathrm{.}0}{3\mathrm{.}0})r^3($Hint: $r^3$ can be computed using $**.$ Use the constant M$\_$PI for the value of pi$.)$

$($Sphere volume notes$)$

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$5216823889370\mathrm{.}9320y?$

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