Question: myonenmath.com E4pts '01 82 ODetails A newsgroup is interested in constructing a 95% confidence interval for the proportion of all Americans who are in favor

 myonenmath.com E4pts '01 82 ODetails A newsgroup is interested in constructinga 95% confidence interval for the proportion of all Americans who arein favor of a new Green initiative. Of the 523 randomly selected

myonenmath.com E4pts '01 82 ODetails A newsgroup is interested in constructing a 95% confidence interval for the proportion of all Americans who are in favor of a new Green initiative. Of the 523 randomly selected Americans surveyed, 436 were in favor of the initiative. Round answers to 4 decimal places where possible. a. With 95% confidence the proportion of all Americans who favor the new Green initiative is between [:] and [:]. b. If many groups of 523 randomly selected Americans were surveyed, then a different confidence interval would be produced from each group. About [:] percent of these confidence intervals will contain the true population proportion of Americans who favor the Green initiative and about [:] percent will not contain the true population proportion. Submit Question myopenmath.oom A scientific study was conducted to determine the hours of sleep that college students get per night. The study surveyed 31 college students and obtained the following data: 8.3, 6.8, 8.9, 6.4, 7.1, 6.8, 6.8, 6.5, 9.2, 7.3, 5.3, 5.6, 7.1, 10.7, 6.5, 7.4, 8.5, 7.3, 8.4, 7.9, 9.8, 7.4, 6, 7.8, 7.3, 6.6, 7.2, 8.7, 7.5, 7.1, 7.4 Assuming the population standard deviation is or = 1.05, construct a 88% confidence interval for the average hours of sleep per night that college students get. We are 88% confident that college students get an sleep per night. Submit Question myopenmath.com A fitness center is interested in finding a 90% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center. Records of 227 members were looked at and their mean number of visits per week was 3.5 and the standard deviation was 1.9. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a distribution. b. With 90% confidence the population mean number of visits per week is between [:] and C] visits. c. If many groups of 227 randomly selected members are studied, then a different confidence interval would be produced from each group. About [:] percent of these confidence intervals will contain the true population mean number of visits per week and about [:] percent will not contain the true population mean number of visits per week

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