n$=13$

p$=0\mathrm{.}1$

Approximately $10\%$ of all people are left$-$handed. Consider $13$ randomly selected people.

Find the probability, to $4$ decimal places:

It is possible when rounded that a probability is $0\mathrm{.}0000$

d$)$ exactly none are left$-$handed.

e$)$ exactly $9$ are left$-$handed.

f$)$ at least $6$ are left$-$handed.

g$)$ at most $6$ are left$-$handed.

h$)$ at least $7$ are left$-$handed.

i$)$ Is $7$ an unusually high number of people that are left$-$handed in a sample of $13$ people?

Yes, because $P(x=7)0\mathrm{.}05$