Consider a liter of aqueous solution containing 1x1020 molecules of receptor R and 1x1020 molecules of...

  

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Consider a liter of aqueous solution containing 1x1020 molecules of receptor R and 1x1020 molecules of ligand L. Consider the reaction: K R+L RL Take Kd values equal to 10-3 and 10-8 M and estimate the percentage of ligand molecules that are bound to the receptor (RL) and the percentage of ligand molecules that are free in solution (L). Find the necessary value of dissociation constant so that the numbers of bound and free ligand molecules are equal. Consider a liter of aqueous solution containing 1x1020 molecules of receptor R and 1x1020 molecules of ligand L. Consider the reaction: K R+L RL Take Kd values equal to 10-3 and 10-8 M and estimate the percentage of ligand molecules that are bound to the receptor (RL) and the percentage of ligand molecules that are free in solution (L). Find the necessary value of dissociation constant so that the numbers of bound and free ligand molecules are equal.

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the solution is hence the percentage of ligand molecules free in the solution is 00001 M and ... View the full answer