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$4.[0/6$ Points$]3/100$ Submissions Used

LarCalc$127\mathrm{.}4\mathrm{.}04$;

Write and evaluate the definite integral that represents the area of the surface generated by revolving the curve on the indicated interval about the $y-$axis.

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$5.[2\mathrm{.}5/5$ Points$]1/100$ Submissions Used

LarCalc$127\mathrm{.}5\mathrm{.}043.$EP$,$

$P_4(x)=x-x^2\frac{5}{6}{x}^3-\frac{5}{6}{x}^4$

$\sqrt[\phantom{2}]{1}$

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$10.[0/1$ Points$]$

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LarCalc$129\mathrm{.}10\mathrm{.}065.$

Use a power series to approximate the value of the definite integral with an error of less than $0\mathrm{.}0001.$ Assume that the integrand is defined as $1$ when $x=0.($Round your answer to four decimal places.$)$

${\displaystyle \underset{0}{\overset{1}{}}}\frac{sin(x)}{x}dx$

${\displaystyle \underset{0}{\overset{1}{}}}\frac{sin(x)}{x}dx$~~${\displaystyle \underset{n=0}{\overset{?}{}}}x(x)=$

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