Question: Need Help Again let the applied field be B=833 mT. But now the two first-order rings have diameters of dia = 6.96 cm and d1b

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Need Help Again let the applied field be B=833 mT. But now

Again let the applied field be B=833 mT. But now the two first-order rings have diameters of dia = 6.96 cm and d1b = 8.40 cm, while the two second-order rings have diameters of d2,a = 11.06 cm and d2b = 12.25 cm. (Relevant parameters for the Fabry- Perot spectrometer are the index of refraction for red light u = 1.4560 and its thickness t=3 mm) From the areal difference between the second-order rings (62;ba), normalized by the areal difference between orders (42,1.c), the Bohr magneton value is is UB = x10 24 J/T

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