Question: Need help answering the question below - the formulas at the bottom are to help answer the problem. Valley Production (VP) manufactures two types of

Need help answering the question below - the formulas at the bottom are to help answer the problem.

Valley Production (VP) manufactures two types of chemicals. One is the Potassium Chloride-Pharmacological grade (KCL-P) and the other is the Potassium Chloride-Technical grade (KCL-T). The accounting department at VP has identified two operating costs units for product manufacture. These costs units are VC and FC units. The KCL-P requires more VC due to the expensive laboratory testing and sanitary handling requirements to meet medical standards. The KCL-T requires more FC in automated equipment due to the high-volume nature of the industrial chemical market.

The CEO has asked you to determine what is the most profitable mix for the two types of products? A breakdown of the cost units and the profits for each product are shown below. Your analysis will include answers to the five questions below and you will recommend a manufacturing location for the two products based on your analysis. Your recommendation will include ALL of the following four items for both products along with your rationale to support your recommendation:

1. Type and amount of labor required

2. Plant size

3. Capital investment requirements

4. Infrastructure requirements

Follow the usual formatting requirements for your response.

KCL-P Profit is $15,000 and each product requires eight VC units and three FC units.

KCL-T Profit is $7,000 and each product requires two VC units and nine FC units.

FC = $5,000/UNIT, VC = $2,000/UNIT

  1. Derive the formulas to show the relationships between the VC & FC for both the KCL-T & KCL-P products using the cost / unit and the number of units used / product.

  1. KCL-T + KCL-P b) KCL-T + KCL-P

VC 2 x 2,000 + 8 x 2,000 = 20,000 VC 3 x 2,000 + 8 x 2,000 = 20,000

FC 9 x 5,000 + 3 x 5,000 = 60,000 FC 9 x 5,000 + 2 x 5,000 = 60,000

c) KCL-T + KCL-P d) KCL-T + KCL-P

VC 2 x 2,000 + 9 x 2,000 = 20,000 VC 3 x 2,000 + 8 x 2,000 = 60,000

FC 8 x 5,000 + 3 x 5,000 = 60,000 FC 9 x 5,000 + 2 x 5,000 = 20,000

KCL-T + KCL-P

  1. VC 9 x 5,000 + 3 x 5,000 = 60,000

FC 2 x 2,000 + 8 x 2,000 = 20,000

2. Derive the linear programming formulas.

  1. 3xKCL-T + 8xKCL-P = 20,000 (VC) b) 2xKCL-T + 9xKCL-P = 20,000 (VC) c) 2xKCL-T + 8xKCL-P = 60,000 (VC)

9xKCL-T + 2xKCL-P = 60,000 (FC) 8xKCL-T + 3xKCL-P = 60,000 (FC) 9xKCL-T + 3xKCL-P = 20,000 (FC)

  1. 8xKCL-T + 2xKCL-P = 20,000 (VC) e) 2xKCL-T + 8xKCL-P = 20,000 (VC)

9xKCL-T + 3xKCL-P = 60,000 (FC) 9xKCL-T + 3xKCL-P = 60,000 (FC)

3. Derive the linear programming ratios.

KCL-T KCL-P KCL-T KCL-P

  1. VC 20,000/2 = 10,000 , 60,000/8 = 7,500 b) VC 20,000/8 = 2,500 , 20,000/2 =10,000

FC 60,000/9 = 6,667 , 20,000/3 = 6,667 FC 60,000/3 = 20,000 , 60,000/9 = 6,667

KCL-T KCL-P KCL-T KCL-P

  1. VC 20,000/9 = 2,222 , 20,000/8 = 2,500 d) VC 20,000/2 = 10,000 , 20,000/8 = 2,500

FC 60,000/2 = 30,000, 60,000/3 = 20,000 FC 60,000/9 = 6,667 , 60,000/3 = 20,000

KCL-T KCL-P

  1. VC 20,000/2 = 10,000 , 20,000/3 = 6,667

FC 60,000/9 = 6,667 , 60,000/8 = 7,500

4. Derive the four corners solutions: 5) Using the letter designations on

KCL-T + KCL-P graph (next page) derive the optimum

  1. FC (0 x $7,000) + (2,500 x $15,000) = $37,500,000 linear programming solution.

VC (6,667 x $7,000) + (0 x $15,000) = $46,669,000 a) (D x $15,000) + (F x $7,000) =

KCL-T + KCL-P b) (E x $7,000) + (B x $15,000) =

  1. VC (0 x $7,000) + (2,500 x $15,000) = $37,500,000 c) (D x $7,000) + (C x $15,000) =

FC (6,667 x $7,000) + (0 x $15,000) = $46,669,000 d) (A x $15,000) + (F x $7,000) =

e) (B x $7,000) + (E x $15,000) =

KCL-T + KCL-P

  1. VC (0 x $7,000) + (2,500 x $15,000) = $46,669,000

FC (6,667 x $7,000) + (0 x $15,000) = $37,500,000

KCL-T + KCL-P

  1. VC (0 x $15,000) + (2,500 x $15,000) = $37,500,000

FC (6,667 x $7,000) + (0 x $7000) = $46,669,000

KCL-T + KCL-P

  1. VC (0 x $7,000) + (2,500 x $7,000) = $37,500,000

FC (6,667 x $15,000) + (0 x $15,000) = $46,669,000

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