Question: Need help answering the questions 2-4 Data: Part 1 - constant mass mass (g) Force (N) acceleration (m/ s2) 0.49 0.8084 Newton's Second Law -

Need help answering the questions 2-4

Need help answering the questions 2-4 Data: Part 1 - constant mass

Data: Part 1 - constant mass mass (g) Force (N) acceleration (m/ s2) 0.49 0.8084 Newton's Second Law - Constant Force 60 0.59 0.9339 70 0.69 1.117 80 0.79 1. 283 Linear Fit for : Data Set | Mass * = math 90 0.88 1. 506 m (Slope): - 0.4414 kg/m/s 100 0.98 1. 735 RMSE : 0.1649 kg Include a graph of acceleration on the x-axis us force on the y-axis. Slope of the line: 1.736 N /m/S (include units) Part 2 - constant force mass (g) acceleration (m/s2) 300 1.915 550 0.8555 800 0 . 5920 acceleration ( m / 52 ) 1.5 1050 0.4433 Include graphs of mass on the x-axis us acceleration on the y-axis and inverse mass on the x-axis us. acceleration on the y-axis. Slope of the line for the second graph only: 0.4414 kg|m/S (include units) 2. Compare the slope of the line to the total accelerating mass. Comment on law is true. the two values, and the expected relationship between them if the second Newton's Second Law - Constant Mass 1.5- Linear Fit for: Data Set | Force m ( Slope ) : 1.736 N/m/s' b ( Y- Intercept): -0.04014 N 3. Newton's Second Law, F = ma can be re-written as: a = F(1/m). How does Correlation : 0.9960 RMSE : 0.05534 N the graph of acceleration versus inverse mass for a system of constant force support this relationship? Force (N 4. Compare the slope of the line to the constant applied force. Comment on the true. two values, and the expected relationship between them if the second law is 0.2 0.4 0 .6 acceleration ( m/s ? ) 0 .8

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